PHP/MySQL | Помогите с выводом description
Тема закрыта by
Viy
Причина: Разобрались
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Причина: Разобрались
Вот код header сайта, помогите с выводом description
$file = mysql_fetch_assoc(mysql_query("SELECT * FROM `#dl_files` WHERE `id`='" . $id . "'"));
$description = $file['description'];
echo '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="viewport" content="width=device-width; initial-scale=1; maximum-scale=1.0; user-scalable=0" />
<meta name="google-site-verification" content="">
<meta name="description" content="'.$description.'">
<meta name="keywords" content="">
<meta name="publisher-url" content="http://site.ru/">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>' . htmlspecialchars($title) . '</title>';
$file = mysql_fetch_assoc(mysql_query("SELECT * FROM `#dl_files` WHERE `id`='" . $id . "'"));
$description = $file['description'];
echo '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="viewport" content="width=device-width; initial-scale=1; maximum-scale=1.0; user-scalable=0" />
<meta name="google-site-verification" content="">
<meta name="description" content="'.$description.'">
<meta name="keywords" content="">
<meta name="publisher-url" content="http://site.ru/">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>' . htmlspecialchars($title) . '</title>';
<meta name="description" content="".$description."">
Александр Григорьевич Лукашенко, Проблема в этом
$file = mysql_fetch_assoc(mysql_query("SELECT * FROM `#dl_files` WHERE `id`='" . $id . "'"));
$description = $file['description'];
$file = mysql_fetch_assoc(mysql_query("SELECT * FROM `#dl_files` WHERE `id`='" . $id . "'"));
$description = $file['description'];
убери #
Александр Григорьевич Лукашенко, таблица в базе так и называется #dl_files
$result = mysql_query("SELECT * FROM #dl_files WHERE id = " . $id . "");
$postrow = mysql_fetch_array($result);
и тогда
<meta name="description" content="'.$postrow[description].'">
Александр Григорьевич Лукашенко, При просмотре исходного кода страницы description не выводится, хотя в таблице БД они есть
ob_start();
$result = mysql_query("SELECT * FROM `#dl_files` WHERE `id` = '. $id .'", $db);
$postrow = mysql_fetch_array($result);
echo '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="viewport" content="width=device-width; initial-scale=1; maximum-scale=1.0; user-scalable=0" />
<meta name="google-site-verification" content="">
<meta name="description" content="'.$postrow['description'].'">
<meta name="keywords" content="">
<meta name="publisher-url" content="http://site.ru/">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>' . htmlspecialchars($title) . '</title>';
ob_start();
$result = mysql_query("SELECT * FROM `#dl_files` WHERE `id` = '. $id .'", $db);
$postrow = mysql_fetch_array($result);
echo '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="viewport" content="width=device-width; initial-scale=1; maximum-scale=1.0; user-scalable=0" />
<meta name="google-site-verification" content="">
<meta name="description" content="'.$postrow['description'].'">
<meta name="keywords" content="">
<meta name="publisher-url" content="http://site.ru/">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>' . htmlspecialchars($title) . '</title>';
include 'путь к файлу с конфигом бд';
$result = mysql_query("SELECT * FROM `#dl_files` WHERE `id` = '. $id .'");
$postrow = mysql_fetch_array($result);
echo '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">;
<html xmlns="http://www.w3.org/1999/xhtml">;
<head>
<meta name="viewport" content="width=device-width; initial-scale=1; maximum-scale=1.0; user-scalable=0" />
<meta name="google-site-verification" content="">
<meta name="description" content="'.$postrow['description'].'">
<meta name="keywords" content="">
<meta name="publisher-url" content="http://site.ru/">;
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>' . htmlspecialchars($title) . '</title>';
и посмотри видит ли скрипт $id
________
посл. ред. 16.04.2016 в 16:15; всего 1 раз(а); by Александр Григорьевич Лукашенк
Сейчас разве мета-теги имеют какой-то смысл?
punkromain, А разве нет?
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