$query22 = mysql_query("SELECT `name_translit`, `name`, `name` FROM `video_dir` WHERE `url` = '0' ORDER BY `name` ASC"); while ($folder22 = mysql_fetch_assoc($query22)) {
?> <div class="th"> <div class="th-holder"> <a href="/tag/<?=$folder22['name_translit'];?>"><span><?=filter($folder22['name']);?></span><img style="width: 100px; height: 180px" src="/style/category/<?=$folder22['name_translit'];?>.jpg" alt="<?=filter($folder22['name']);?>" title="<?=filter($folder['name']);?>"></a> <div class="video_quality"><?= mysql_result(mysql_query("SELECT COUNT(*) FROM `video_file` WHERE `teg` like '%". $folder22['name'] ."%' AND `visible` = '1'"), 0);?></div></a>
</div> </div>
<? } ?>
Нужно именно чтобы при выводе вырезалось слово "жанр" с переменной $folder22['name']
________ посл. ред. 02.06.2019 в 16:28; всего 1 раз(а); by Boy